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Question #40579

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all ordered triplets (x,y,z)(x, y, z) of non-negative integers satisfying the following conditions: x+y+z≤15x + y + z \le 15 2x+y+z−4≥1x+y+z−9\frac{2}{x+y+z-4} \ge \frac{1}{x+y+z-9} Find the total number of elements in the set SS.

Options

  • A.

    386

  • B.

    256

  • C.

    130

  • D.

    816

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Distributing Identical Items (Stars and Bars)|Bounded vs Unbounded Regions|Cross Multiplication Trap

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of combinatorics (Stars and Bars) with algebraic inequalities.

The core trap lies in the 'Cross Multiplication Trap' (Concept 62).

Students often blindly cross-multiply 2k−4≥1k−9\frac{2}{k-4} \ge \frac{1}{k-9} to get 2k−18≥k−4  ⟹  k≥142k-18 \ge k-4 \implies k \ge 14, completely missing the region where the product of the denominators is negative (4<k<94 < k < 9).

This leads them to calculate only the solutions for k∈{14,15}k \in \{14, 15\}, yielding the trap answer 256.

A rigorous approach requires bringing all terms to one side and using the wavy curve method to identify all valid bounded regions before applying the (n+r−1r−1)\binom{n+r-1}{r-1} distribution formula.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterPermutations and Combinations - Class 11
ConceptDistributing Identical Items (Stars and Bars)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree