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Question #40560
The Question
Let be the number of distinct arrangements of 3 identical red balls and 2 identical blue balls in a straight line such that the two blue balls are not adjacent. Let . If , then the value of is
Options
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- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Specialist
Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.
Concepts Behind This Question
Fundamental Principle of Counting (FPC)|Gap Method (Non-adjacency)|Indeterminate Forms|Chain Rule Complexity
Why This Question Is Tricky
Common Mistakes
This question fuses Discrete Mathematics with Calculus, creating a lethal collision of concepts.
The student must first correctly apply the Gap Method to find the combinatorial constant .
A common trap is treating identical items as distinct or forgetting the non-adjacency constraint.
This is then embedded in a indeterminate limit, requiring L'Hopital's rule or Taylor expansion.
Finally, the resulting function is subjected to a multi-layered chain rule.
An error in propagates exponentially into the exponent, and forgetting internal derivatives during the chain rule (such as the derivative of the inverse tangent or the natural logarithm) leads directly to the carefully crafted distractor options.
Quick Facts About This Question
Question Information
| Subject | Mathematics |
| Chapter | Permutations and Combinations - Class 11 |
| Concept | Fundamental Principle of Counting (FPC) |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |