Start Learning Free

Before You Begin

Question #40517

Difficulty: 8/10 | 🟢 Free

The Question

Let A=[aij]A = [a_{ij}] be a 3×33 \times 3 matrix where aija_{ij} is the number of integers kk satisfying the inequality k2−(i+2j)k+2ij≤0k^2 - (i+2j)k + 2ij \le 0 for 1≤i,j≤31 \le i, j \le 3. Let BB be the 3×33 \times 3 matrix such that for any 3×33 \times 3 matrix YY, the product BYBY represents the matrix obtained by first swapping the first and second rows of YY, and then swapping the second and third rows of the resulting matrix. Consider the system of linear equations MX=CM X = C, where M=(A+B)(A−B)−A2+B2M = (A+B)(A-B) - A^2 + B^2 and C=(−4−20)C = \begin{pmatrix} -4 \\ -2 \\ 0 \end{pmatrix}. If X=(xyz)X = \begin{pmatrix} x \\ y \\ z \end{pmatrix} is the unique solution to the system, find the value of x+y+zx + y + z.

Options

  • A.

    2

  • B.

    -4

  • C.

    0

  • D.

    4

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Sign Flipping Rule|System of Linear Equations (Cramer/Inverse)|Matrix Multiplication Non-Commutativity|Characteristic Equation

Why This Question Is Tricky

Common Mistakes

This question tests the student's vigilance against the 'Non-Commutativity' trap in matrix algebra, combined with the 'Sign Flipping Rule' of determinants and row operations.

Students often mistakenly assume (A+B)(A−B)=A2−B2(A+B)(A-B) = A^2 - B^2, which would lead to M=0M = 0 and the false conclusion that the system has no unique solution.

By correctly expanding the expression to M=BA−ABM = BA - AB, the student must then construct AA from the quadratic inequality (yielding a specific integer matrix) and BB from the described row operations (yielding a cyclic permutation matrix).

The row operations implicitly test the sign flipping rule, as BB is formed by two row swaps (det⁡(B)=1\det(B)=1).

Finally, applying Cramer's rule or Gaussian elimination to MX=CMX = C yields the correct sum of the solution components.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterLinear Inequalities - Class 11
ConceptSign Flipping Rule
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree