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Question #40507

Difficulty: 8/10 | 🟢 Free

The Question

Let aa be the minimum value of the function P(x)=x2−2x+2P(x) = x^2 - 2x + 2 and bb be the maximum value of the function Q(x)=−x2+10x−20Q(x) = -x^2 + 10x - 20. Consider the function F(x)F(x) defined on [a,b][a, b] by F(x)=∫axln⁡∣t2−4t+3∣ dtF(x) = \int_{a}^{x} \ln|t^2 - 4t + 3| \, dt Let SS be the set of all points x∈(a,b)x \in (a, b) such that F′(x)=0F'(x) = 0. Find the sum of all elements in SS.

Options

  • A.

    4+24 + \sqrt{2}

  • B.

    2+22 + \sqrt{2}

  • C.

    44

  • D.

    22

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Maximum/Minimum of Quadratic Expressions|Newton-Leibniz Formula with variable limits|Logarithmic Integration Modulus

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Newton-Leibniz formula combined with the 'Logarithmic Integration Modulus' trap.

Students must first determine the integration interval by finding the extrema of two quadratics.

The core trap lies in solving F′(x)=ln⁡∣x2−4x+3∣=0F'(x) = \ln|x^2 - 4x + 3| = 0.

A common mistake is to ignore the absolute value, solving only x2−4x+3=1x^2 - 4x + 3 = 1 and missing the root derived from x2−4x+3=−1x^2 - 4x + 3 = -1.

Because the vertex of the quadratic inside the logarithm drops below zero, the modulus is activated, making x=2x=2 a valid critical point where the derivative is zero.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterComplex Numbers and Quadratic Equations - Class 11
ConceptMaximum/Minimum of Quadratic Expressions
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree