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Question #40487

Difficulty: 8/10 | 🟢 Free

The Question

Let z1,z2,z3z_1, z_2, z_3 be the roots of the equation z3−5z2+17z−13=0z^3 - 5z^2 + 17z - 13 = 0. Let M(z)M(z) be a 4×44 \times 4 matrix whose entries are given by mjk=∣wj−wk∣2m_{jk} = |w_j - w_k|^2 for 1≤j,k≤41 \le j, k \le 4, where w1=zw_1 = z, w2=z1w_2 = z_1, w3=z2w_3 = z_2, and w4=z3w_4 = z_3. Let CC be the locus of points z∈Cz \in \mathbb{C} such that det⁡(M(z))=0\det(M(z)) = 0. If AA is the area of the region bounded by CC, find the value of Aπ\frac{A}{\pi}.

Options

  • A.

    13

  • B.

    16

  • C.

    25

  • D.

    36

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Locus Problems via Transformation|Determinant Product Rule|Factor Theorem in Determinants

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to connect determinant properties with geometric loci.

The primary trap lies in the expansion of the squared distance ∣wj−wk∣2|w_j - w_k|^2.

A student might incorrectly group the terms into a sum of three products, mistakenly concluding that the 4×44 \times 4 matrix M(z)M(z) is a product of 4×34 \times 3 and 3×43 \times 4 matrices.

This would lead to the erroneous conclusion that det⁡(M(z))=0\det(M(z)) = 0 for all zz, implying the locus is the entire complex plane.

The correct approach requires recognizing the 4-term expansion, factoring M(z)M(z) into two 4×44 \times 4 matrices, and identifying that the vanishing determinant yields the standard determinantal equation of a circumcircle.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterComplex Numbers and Quadratic Equations - Class 11
ConceptLocus Problems via Transformation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree