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Question #40482

Difficulty: 8/10 | 🟢 Free

The Question

Let z=(1−i)8(3−i)6(−1+i3)3z = \frac{(1 - i)^8 (\sqrt{3} - i)^6}{(-1 + i\sqrt{3})^3}. If θ=Arg(z)\theta = \text{Arg}(z) denotes the principal argument of zz, find the value of 2sin⁡(θ2)+4sin⁡(θ3)2 \sin\left(\frac{\theta}{2}\right) + 4 \sin\left(\frac{\theta}{3}\right)

Options

  • A.

    2+232 + 2\sqrt{3}

  • B.

    −2−23-2 - 2\sqrt{3}

  • C.

    −2+23-2 + 2\sqrt{3}

  • D.

    2−232 - 2\sqrt{3}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

De Moivre’s Theorem Applications|Argument and Principal Value|Closed vs Open Intervals

Why This Question Is Tricky

Common Mistakes

This question tests the application of De Moivre's Theorem and the precise definition of the principal argument of a complex number.

Students often compute the raw sum of arguments (here, −5π-5\pi) and either use it directly or incorrectly reduce it to −π-\pi by assuming the principal range is [−π,π)[-\pi, \pi) or by simple modulo arithmetic without checking boundary inclusion.

The standard principal argument range is (−π,π](-\pi, \pi], meaning negative real numbers have an argument of π\pi.

Using −5π-5\pi or −π-\pi leads to incorrect sign evaluations in the final trigonometric expression, perfectly mapping to the distractor options.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterComplex Numbers and Quadratic Equations - Class 11
ConceptDe Moivre’s Theorem Applications
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree