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Question #40475

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all complex numbers zz satisfying Re(z)=Im(z)\text{Re}(z) = \text{Im}(z). For a fixed angle θ∈[0,2π)\theta \in [0, 2\pi), a point PP in 3D space is defined by its coordinates (X,Y,Z)(X, Y, Z) where: X=Re(zeiθ),Y=Im(zeiθ),Z=Re(z)X = \text{Re}(z e^{i\theta}), \quad Y = \text{Im}(z e^{i\theta}), \quad Z = \text{Re}(z) Let Π1\Pi_1 and Π2\Pi_2 be two planes given by the equations: Π1:2X+3Y−2Z=1\Pi_1: 2X + 3Y - 2Z = 1 Π2:X+2Y−Z=1\Pi_2: X + 2Y - Z = 1 If there exists a plane Π\Pi passing through the line of intersection of Π1\Pi_1 and Π2\Pi_2 such that the locus of PP (as the complex number zz varies in SS) lies entirely in Π\Pi, find the sum of all possible values of θ\theta.

Options

  • A.

    2π2\pi

  • B.

    π\pi

  • C.

    3π3\pi

  • D.

    4π3\frac{4\pi}{3}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Euler's Form and Rotations|Equation of plane through intersection|Line lying in a plane

Why This Question Is Tricky

Common Mistakes

This question tests the concept of a line lying entirely within a plane, disguised through complex number rotations and 3D projections.

The primary trap is failing to recognize that the locus of the rotated complex point forms a line parameterized by tt, which passes through the origin.

Students often attempt to solve the intersection directly, overlooking that for a plane to contain a line passing through the origin, the plane itself must pass through the origin.

This forces the parameter λ=−1\lambda = -1 in the family of planes.

Ignoring this constant term constraint leads to a linear dependency conflict, making it impossible to isolate θ\theta correctly.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterComplex Numbers and Quadratic Equations - Class 11
ConceptEuler's Form and Rotations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree