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Question #40474

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all 2×22 \times 2 matrices A=(z1z2z3z4)A = \begin{pmatrix} z_1 & z_2 \\ z_3 & z_4 \end{pmatrix} with complex entries such that ATA=IA^T A = I, where II is the identity matrix. If ∣zk∣=1|z_k| = 1 for k=1,2,3,4k=1,2,3,4, find the number of elements in SS.

Options

  • A.

    0

  • B.

    8

  • C.

    16

  • D.

    32

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Euler's Form and Rotations|Orthogonal Matrix Conditions|Modulus Sign Dependency

Why This Question Is Tricky

Common Mistakes

This problem tests the intersection of orthogonal matrix properties and complex geometry.

A common trap is the 'Modulus Sign Dependency': students intuitively associate ATA=IA^T A = I with real rotation/reflection matrices, assuming z1=cos⁡θz_1 = \cos\theta and z3=sin⁡θz_3 = \sin\theta.

However, since ∣z1∣=1|z_1|=1, a real z1z_1 implies z1=±1z_1 = \pm 1, leading to z12+z32=2≠1z_1^2 + z_3^2 = 2 \neq 1, which incorrectly yields 0 solutions.

The key is recognizing that the orthogonality condition applies to the squares of the complex entries, forcing z12z_1^2 and z32z_3^2 to be conjugate complex roots of unity (e±iπ/3e^{\pm i\pi/3}) that sum to 1, thereby unlocking the finite set of valid transformation matrices.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterComplex Numbers and Quadratic Equations - Class 11
ConceptEuler's Form and Rotations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree