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Question #40443

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=∣sin⁡xcos⁡xesin⁡xcos⁡x−sin⁡xesin⁡xcos⁡x−sin⁡x−cos⁡xesin⁡x(cos⁡2x−sin⁡x)∣f(x) = \begin{vmatrix} \sin x & \cos x & e^{\sin x} \\ \cos x & -\sin x & e^{\sin x}\cos x \\ -\sin x & -\cos x & e^{\sin x}(\cos^2 x - \sin x) \end{vmatrix}. Find the number of critical points of f(x)f(x) in the interval [0,2π][0, 2\pi].

Options

  • A.

    4

  • B.

    2

  • C.

    3

  • D.

    1

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Monotonicity and Boundedness|Differentiation of Determinants|Singular vs. Non-Singular Threshold

Why This Question Is Tricky

Common Mistakes

The question tests the evaluation of a Wronskian-like determinant and the subsequent monotonicity analysis.

The primary trap is the 'Singular Threshold' fallacy: students often assume that the critical points of a determinant function f(x)=det⁡(A(x))f(x) = \det(A(x)) occur exclusively where the matrix becomes singular (f(x)=0f(x) = 0).

Here, det⁡(A)=0\det(A) = 0 simplifies to sin⁡2x+sin⁡x−2=0\sin^2 x + \sin x - 2 = 0, which only yields x=π/2x = \pi/2.

Relying solely on this threshold causes students to miss the other three critical points generated by the chain rule and the embedded quadratic sin⁡2x+3sin⁡x−1=0\sin^2 x + 3\sin x - 1 = 0.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterTrigonometric Functions - Class 11
ConceptMonotonicity and Boundedness
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree