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Question #40442

Difficulty: 8/10 | 🟢 Free

The Question

Find the complete set of all real values of aa for which the equation ∣3sin⁡x−cos⁡x∣+∣sin⁡x+3cos⁡x∣=ax2−2ax+a+22|\sqrt{3} \sin x - \cos x| + |\sin x + \sqrt{3} \cos x| = a x^2 - 2a x + a + 2\sqrt{2} has at least one real solution.

Options

  • A.

    (−∞,0](-\infty, 0]

  • B.

    [0,∞)[0, \infty)

  • C.

    (0,∞)(0, \infty)

  • D.

    {0}\{0\}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Monotonicity and Boundedness|Triangle Inequality Mind Games|Modulus Inequality Logic

Why This Question Is Tricky

Common Mistakes

This question constructs a 'Lethal Collision' between a bounded trigonometric function and a quadratic polynomial.

The core trap lies in the boundary conditions of the modulus inequality.

Students frequently calculate the maximum of the LHS (222\sqrt{2}) and the minimum of the RHS (222\sqrt{2} for a>0a > 0), concluding that solutions exist for a≥0a \ge 0 by simply equating the bounds.

However, they fail to verify if the domain values (xx-coordinates) where these bounds are achieved actually coincide.

Since the RHS minimum occurs at x=1x=1 and the LHS maximum occurs at x=5π/12+nπ/2x = 5\pi/12 + n\pi/2, they never simultaneously reach 222\sqrt{2}.

The true solution requires applying the Intermediate Value Theorem for a<0a < 0, where the inverted parabola must intersect the bounded trigonometric wave.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterTrigonometric Functions - Class 11
ConceptMonotonicity and Boundedness
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree