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Question #40408

Difficulty: 8/10 | 🟢 Free

The Question

Let I=∫02πdx2+cos⁡x+∣sin⁡x∣I = \int_0^{2\pi} \frac{dx}{2 + \cos x + |\sin x|}. Which of the following inequalities is true?

Options

  • A.

    I≥2πI \ge \sqrt{2}\pi

  • B.

    π≤I<2π\pi \le I < \sqrt{2}\pi

  • C.

    3π4≤I<π\frac{3\pi}{4} \le I < \pi

  • D.

    I<3π4I < \frac{3\pi}{4}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Monster

Ultra-high difficulty questions designed to test your limit, stamina, and deep conceptual understanding.

Concepts Behind This Question

Tangent Half-Angle Substitution|Inequalities in Definite Integrals|Differentiability vs Continuity

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to handle absolute values in trigonometric integrals and rigorously bound the result.

The primary trap lies in the Weierstrass substitution t=tan⁡(x/2)t = \tan(x/2).

If a student blindly applies this substitution over the entire interval [0,2π][0, 2\pi], the term ∣sin⁡x∣|\sin x| transforms to 2∣t∣1+t2\frac{2|t|}{1+t^2}, creating a non-differentiable cusp at t=0t=0 in the tt-domain.

Students commonly drop the absolute value, incorrectly integrating the smooth function 2t2+2t+3\frac{2}{t^2+2t+3} over (−∞,∞)(-\infty, \infty) to get 2π\sqrt{2}\pi, leading them to choose the invalid upper bound (Option A).

Correct evaluation requires splitting the integral to respect the cusp, followed by precise trigonometric bounding using Taylor series properties (arctan⁡x<x\arctan x < x) to find the tight inequality.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterTrigonometric Functions - Class 11
ConceptTangent Half-Angle Substitution
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree