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Question #40405

Difficulty: 8/10 | 🟢 Free

The Question

Evaluate the definite integral I=∫−1−1/2(cos⁡−1(4x3−3x)+3cos⁡−1(−x))dxI = \int_{-1}^{-1/2} \left( \cos^{-1}(4x^3 - 3x) + 3\cos^{-1}(-x) \right) dx

Options

  • A.

    π2\frac{\pi}{2}

  • B.

    3π2\frac{3\pi}{2}

  • C.

    −π-\pi

  • D.

    5π2\frac{5\pi}{2}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Conditional Identity Constraints|Variable Transformation Substitution|Principal Value Branch Boundaries|The Quadrant Adjustment Logic

Why This Question Is Tricky

Common Mistakes

This question tests the 'Lethal Collision' between variable substitution and the Principal Value Branch of inverse trigonometric functions.

Students often blindly apply the standard identity cos⁡−1(4x3−3x)=3cos⁡−1x\cos^{-1}(4x^3 - 3x) = 3\cos^{-1}x, which is only valid for x∈[1/2,1]x \in [1/2, 1].

For the interval x∈[−1,−1/2]x \in [-1, -1/2], the substituted angle 3θ3\theta falls in the range [2π,3π][2\pi, 3\pi], requiring a mandatory quadrant adjustment to 3θ−2π3\theta - 2\pi.

Failing to account for this specific 2π2\pi phase shift leads directly to an unadjusted integrand of 3π3\pi, trapping the student into selecting the distractor 3π/23\pi/2.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterTrigonometric Functions - Class 11
ConceptConditional Identity Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree