Start Learning Free

Before You Begin

Question #40398

Difficulty: 8/10 | 🟢 Free

The Question

Let f(x)=3sin⁡−1(3sin⁡x+4cos⁡x5)−2cos⁡−1(5cos⁡x−12sin⁡x13)f(x) = 3 \sin^{-1}\left( \frac{3\sin x + 4\cos x}{5} \right) - 2 \cos^{-1}\left( \frac{5\cos x - 12\sin x}{13} \right). Find the value of f′(3π4)f'\left( \frac{3\pi}{4} \right).

Options

  • A.

    -1

  • B.

    1

  • C.

    5

  • D.

    -5

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Bridge

Practice problems that bridge the gap between foundational theory and advanced practical application.

Concepts Behind This Question

Compound Angle Expansion|Derivative of Implicit Inverse Forms|The Quadrant Adjustment Logic

Why This Question Is Tricky

Common Mistakes

This question tests the 'Quadrant Adjustment Logic' within the differentiation of implicit inverse trigonometric functions.

Students often blindly apply the chain rule or assume sin⁡−1(sin⁡θ)=θ\sin^{-1}(\sin \theta) = \theta and cos⁡−1(cos⁡θ)=θ\cos^{-1}(\cos \theta) = \theta, which leads to an incorrect derivative of 3(1)−2(1)=13(1) - 2(1) = 1.

The trap lies in the hidden domain constraints: the compound angles x+αx+\alpha and x+βx+\beta at x=3π/4x = 3\pi/4 fall into the second/third quadrants where the principal branches shift.

Specifically, x+α∈(π/2,3π/2)x+\alpha \in (\pi/2, 3\pi/2) forces sin⁡−1(sin⁡θ)=π−θ\sin^{-1}(\sin \theta) = \pi - \theta, and x+β∈(π,2π)x+\beta \in (\pi, 2\pi) forces cos⁡−1(cos⁡θ)=2π−θ\cos^{-1}(\cos \theta) = 2\pi - \theta.

Recognizing these boundary crossings is essential to extract the correct negative slopes before differentiation.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterTrigonometric Functions - Class 11
ConceptCompound Angle Expansion
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree