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Question #40318

Difficulty: 8/10 | 🟢 Free

The Question

Let SS be the set of all points (x,y)∈Z2(x,y) \in \mathbb{Z}^2 that simultaneously satisfy the following four inequalities: I. max⁡(y−x,4−y)≥0\max(y - x, 4 - y) \ge 0 II. max⁡(y+x,4−y)≥0\max(y + x, 4 - y) \ge 0 III. max⁡(y−x,y−5)≥0\max(y - x, y - 5) \ge 0 IV. max⁡(y+x,y−5)≥0\max(y + x, y - 5) \ge 0

Evaluate the sum: ∑(x,y)∈S2−y\sum_{(x,y) \in S} 2^{-y}

Options

  • A.

    6

  • B.

    8316\frac{83}{16}

  • C.

    1316\frac{13}{16}

  • D.

    ∞\infty

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Specialist

Targeted practice for niche, high-difficulty concepts that frequently appear in JEE Advanced exams.

Concepts Behind This Question

Set Identity Laws|Redundant Constraints|Unbounded Region Trap|Sigma Notation Properties

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to apply Set Identity Laws (specifically the Distributive Law) to simplify a system of logical inequalities.

The primary trap is the 'Unbounded Region Trap' combined with 'Redundant Constraints'.

Students often mistakenly assume that the presence of the terms 4−y4-y and y−5y-5 implies the region is bounded by y≤4y \le 4.

If they fail to simplify the logical propositions (A∨C)∧(A∨¬C)≡A(A \lor C) \land (A \lor \neg C) \equiv A, they will incorrectly intersect the region with y≤4y \le 4, leading to a finite sum over a bounded triangle (yielding the distractor 83/16).

Recognizing the redundancy reveals the region is unbounded (y≥∣x∣y \ge |x|), requiring the evaluation of a convergent infinite double geometric series (or an arithmetico-geometric progression), testing their rigor with Sigma notation properties over infinite index sets.

Quick Facts About This Question

Question Information

SubjectMathematics
ChapterSets - Class 11
ConceptSet Identity Laws
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree